Use Mixed congreuential method to generate a sequence of random numbers with X0 = 27, n = 17, m = 100 and c = 43.

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Suresh Chand · Accepted Answer

Solution Given, X0 = 27,  α = 17, c= 43 & m=100 We have, Xi+1 = (α Xi + c) mod m Mixed Congruential Method: c ≠ 0 & Ri =Xi/m, The sequence of random numbers is calculated as follows: X0 = 27 R0 = 27/100 = 0.27 X1 = (α X0 + c) mod m = (17*27+43) mod 100 = 502 mod 100 = 2 R1 = 2/100 = 0.02 X2 = (α X1 + c) mod m = (17*2+43) mod 100 = 77 mod 100 = 77 R2 = 77/100 = 0.77 X3 = (α X2 + c) mod m = (17*77+43) mod 100 = 1352 mod 100 = 52 R3 = 52/100 = 0.52 X4 = (α X3 + c) mod m = (17*52+43) mod 100 = 927 mod 100 = 27 R4 = 27/100 = 0.27 Therefore, The sequence of random integers is 27, 02, 77, 52, 27 & so on. The sequence of random numbers is 0.27, 0.02, 0.77, 0.52, 0.27 & so on.

Use Mixed congreuential method to generate a sequence of random numbers with X₀ = 27, n = 17, m = 100 and c = 43.

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Use Mixed congreuential method to generate a sequence of random numbers with X0 = 27, n = 17, m = 100 and c = 43.

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Use Mixed congreuential method to generate a sequence of random numbers with X₀ = 27, n = 17, m = 100 and c = 43.