A sample size 100 produces the sample mean 16. Assuming population standard deviation 3, compute 99% confidence level for population.

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Suresh Chand · Accepted Answer

Solution: Given n = 100 mean (x̄) = 16 Standard deviation(σ) = 9 We know, 1 - α = 0.99 or, α = 0.01 Zα/2 = Z0.005 = 2.575 (Using Normal Table) Then Standard error, SE(x̄) = (frac{s}{sqrt{n}} = frac{9}{10} = 0.9) And, 99% Confidence interval for μ, x̄ ± Zα/2 . SE(x̄) = 16 ± 2.575 . 0.9 = (18.3175, 13.6825) Hence, 99% confidence interval is (18.3175, 13.6825)

A sample size 100 produces the sample mean 16. Assuming population standard deviation 3, compute 99% confidence level for population.

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A sample size 100 produces the sample mean 16. Assuming population standard deviation 3, compute 99% confidence level for population.

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