The table shows the corresponding vales of the three variables Y, X1 and X2

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Suresh Chand · Accepted Answer

Solution: Y X1 X2 X12 X22 Y2 X1Y X2Y X1X2 6 1 3 1 9 36 6 18 3 11 3 -1 9 1 121 33 -11 -3 10 2 2 4 4 100 20 22 4 7 -2 4 4 16 49 -14 28 -8 5 3 7 9 49 25 15 35 21 12 6 3 36 9 144 72 36 18 ΣY = 51 ΣX1 = 13 ΣX2 = 18 ΣX12 = 63 ΣX22 = 88 ΣY2 = 475 ΣX1Y = 132 ΣX2Y = 128 ΣX1X2 = 35 Y = a + b1X1 + b2X2    …… (i) By using least square method, normal equations ΣY = na + b1ΣX1 + b2ΣX2     …… (ii) ΣX1Y = aΣX1 + b1ΣX12 + b2ΣX1X2   ….. (iii) ΣX2Y = aΣX2 + b1ΣX1X2 + b2ΣX22   …..(iv) Now, substituting the values min equation in (ii), (iii) and (iv) 51 = 6a + 13b1 + 18b2   …… (a) 132 = 13a + 63b1 + 35b2   …… (b) 128 = 18a+ 35b1 + 88b2   ……. (c) Solving equation (a), (b) and (c), we get a = 9.35 b1 = 0.54 b2 = -0.67 Putting the value of a, b1, b2 in equation (1), We get Y = 9.35 + 0.54X1 - 0.67X2    …….. (d) If X1 = -9 and X2 = 4 then Y = 9.35 + 0.54 × (-9) - 0.67 × 4 = 1.81 Therefore, The required value of Y is 1.81 There may be error in calculation. Please follow the steps only. If you find any error then please report to us.

The table shows the corresponding vales of the three variables Y, X1 and X2

Y 6 11 10 7 5 12

X1 1 3 2 -2 3 6

X2 3 -1 2 4 7 3

Estimate the Y when X1 = -9 and X2 = 4

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The table shows the corresponding vales of the three variables Y, X1 and X2 Y 6 11 10 7 5 12 X1 1 3 2 -2 3 6 X2 3 -1 2 4 7 3 Estimate the Y when X1 = -9 and X2 = 4

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The table shows the corresponding vales of the three variables Y, X1 and X2

Y 6 11 10 7 5 12

X1 1 3 2 -2 3 6

X2 3 -1 2 4 7 3

Estimate the Y when X1 = -9 and X2 = 4