A 12 | C 19 | B 10 | D 10 |

C 17 | B 13 | D 7 | A ? |

B 21 | D 11 | A 6 | C 19 |

D 12 | A 7 | C 27 | B 18 |

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Login Now**Solution:**

Let x be the missing observation.

Treatment | Block | |||

I | II | III | IV | |

A | 12 | x | 6 | 7 |

B | 10 | 13 | 21 | 18 |

C | 19 | 17 | 19 | 27 |

D | 10 | 7 | 11 | 12 |

Here,

Number of blocks (r) = 4

Number of column (C) = 4

Number of Treatment (k) = 4

Sum of remaining values in the block with missing observation(b) = 13 + 17 + 7 = 37

Sum of remaining values of the treatment and with the missing observation(T) = 12 + 6 + 7 = 25

Grand Total (G) = 209

Now,

\(x = \frac{rB + KT – G}{(r-1)(C-1)}\)

\(= \frac{4 \times 37 + 4 \times 25 – 209}{(4-1)(4-1)}\)

= 4.33

Therefore, the missing observation is 4.33

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