This answer is restricted. Please login to view the answer of this question.

Login Now**Solution:**

Sample Size (n) = 65

Sample mean (x̄) = 992

Sample standard deviation(σ) = 15

Population mean(μ) = 979

Level of significance(α) = 5% = 0.05

**Problem to Test:**

**H**_{0}**: **Average pass is 979 (μ = 979)

**H**_{1}**: **Average pass is more than 979 (μ > 979)

**Test Statistics:**

\(z = \frac{\overline{X} – μ}{\frac{σ}{\sqrt{n}}}\)

\( = \frac{992 – 979}{\frac{15}{\sqrt{65}}}\)

= 6.987

**Critical Value:**

At α = 5% = 0.05, the critical value (Z_{α}) = Z_{0.05} = 1.645

**Decision:**

Here, |z| = 6.987 > Z_{tab} = 1.645, reject H_{0} at 5% level of significance.

**Conclusion:**

The claim of manufacture is correct.

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## Discussion