In a block of address, we know the IP Address of one host is 192.34.12.56/28. What are the first address(network address)  and the last address (limited broadcast address) in this block?

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Given,

IP Address = 192.34.12.56/28

Subnet mask: 11111111.11111111.11111111.11110000 (255.255.255.240)

Total Subnet = 24 = 16

Total host = 24 = 16

Usable host = 16 – 2 = 14

Valid Subnets (4th octet) = 256 – 246 = 16

Subnet Network IP Usable IP Pool (1st host and last host) Broadcast IP
First Host Last Host
192.34.12.0 192.34.12.1 192.34.12.14 192.34.12.15
192.34.12.16 192.34.12.17 192.34.12.30 192.34.12.31
192.34.12.32 192.34.12.33 192.34.12.46 192.34.12.47
192.34.12.48 192.34.12.49 192.34.12.62 192.34.12.63
192.34.12.64 192.34.12.65 192.34.12.78 192.34.12.79
192.34.12.80 192.34.12.81 192.34.12.94 192.34.12.95
192.34.12.96 192.34.12.97 192.34.12.110 192.34.12.111
192.34.12.112 192.34.12.113 192.34.12.126 192.34.12.127
192.34.12.128 192.34.12.129 192.34.12.142 192.34.12.143
192.34.12.144 192.34.12.145 192.34.12.158 192.34.12.159
192.34.12.160 192.34.12.161 192.34.12.174 192.34.12.175
192.34.12.176 192.34.12.177 192.34.12.190 192.34.12.191
192.34.12.192 192.34.12.193 192.34.12.206 192.34.12.207
192.34.12.208 192.34.12.209 192.34.12.222 192.34.12.223
192.34.12.224 192.34.12.225 192.34.12.238 192.34.12.239
192.34.12.240 192.34.12.241 192.34.12.254 192.34.12.255

First Address (Network Address) = 192.34.12.48/28

First host = 192.34.12.49/28

Last host = 192.34.12.62/28

Broadcast address = 192.34.12.63/28

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