Divide 3x^2+ 4x +3 by 5x +6 over GF(7).

Question

Suresh Chand · Accepted Answer

Solution: (begin{array}{ll} 5x + 6 | overline{3x^2 + 4x + 3}| 2x + 4 qquad quad 3x^2 + 5x qquad quad - enspace enspace - qquad quad rule{6em}{0.5px}  qquad quad -x + 3 qquad quad = 6x + 3 qquad (mode 7) qquad quad 20x + 24 qquad quad - enspace enspace - qquad quad rule{6em}{0.5px}  qquad quad -14x + 14 qquad quad 0 qquad qquad qquad (mod 7) end{array}) Q = 2x + 4 R = 0

Divide 3x² + 4x +3 by 5x +6 over GF(7).

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Divide 3x2 + 4x +3 by 5x +6 over GF(7).

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Divide 3x² + 4x +3 by 5x +6 over GF(7).