An oscillating block of mass 250 g takes 0.15 sec to move between the endpoints of motion, which are 40cm apart.

  1. What is the frequency of the motion?
  2. What is the amplitude of the motions?
  3. What is the forces constant of the spring?


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Here is given, block of mass (m) = 250gm = 250 x 10-3 kg

Time (t) = 0.15 sec

Displacement (x) = 40cm = 40 x 10-2m

Frequency (f) = ?

Force constant (k) = ?

We know,

a.  f  = 1/t = 1/0.15 = 6.67 rev sec-1

b. Amplitude (xm) =

\(\frac{40 \times 10^{-2}}{2}\) = 20 x 10-2 m

c. Again we know that

\(2\pi f = \sqrt{\frac{k}{m}}\)

\(4\pi^2f^2 = \frac{k}{m}\)

\(k = 4\pi^2f^2 m\)

\(k = 4\pi^{2}(6.67)^2 \times 250 \times 10^{-3}\)

k = 439.08 Nm-1

Hence, required frequency, amplitude and force constant are 6.67 rev s-1, 20 x 10-2m and 439.08 Nm-1

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