A current of 50A is established in a slab of copper 0.5cm thick and 2 cm wide .The slab is placed in a magnetic field B of 1.5 T. The magnetic field is perpendicular to the plane of the slab and to the current .The free electron concentration in copper is 8.4 × 1028 electrons/m3? . What will be the magnitude of the gall voltage across the width of the slab?

This answer is restricted. Please login to view the answer of this question.

Login Now

Solution:

User Loaded Image | CSIT Guide

 

Current (I) = 50A

Thickness of cupper (x) = 0.5cm

Width of copper slab(b) = 2cm

Magnetic Field(B) = 1.5T

Free electron concentration (N) = \(8.4  \times 10^{28}\) electrons/m3

Magnitude of Hall Voltage(VH) = ?

We know that,

\(V_{H} = \frac{IB b}{NqA}\)

\(V_{H} = \frac{50 \times 1.5 \times 2 \times 10^{-2}}{8.4 \times 10^{28} \times 1.6 \times 10^{-19} \times 10^{-4}}\)

\(V_{H} = 1.12 \times 10^{-6} V\)

Hence required hall voltage is \(1.12 \times 10^{-6} V\).

If you found any type of error on the answer then please mention on the comment or report an answer or submit your new answer.
Leave your Answer:

Click here to submit your answer.

Discussion
0 Comments
  Loading . . .