What is dynamic memory allocation? Discuss the use of malloc() in dynamic memory allocation with example.

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As we know, an array is a collection of a fixed number of values. Once the size of an array is declared, you cannot change it.

Sometimes the size of the array you declared may be insufficient. To solve this issue, you can allocate memory manually during run-time. This is known as dynamic memory allocation in C programming.

To allocate memory dynamically, library functions are malloc(), calloc(), realloc() and free() are used. These functions are defined in the header file.


The name “malloc” stands for memory allocation.

The malloc() function reserves a block of memory of the specified number of bytes. And, it returns a pointer of void which can be casted into pointers of any form.


ptr = (castType*) malloc(size);


#include <stdio.h>
#include <stdlib.h>

int main()

    int* ptr;
    int n, i;

    // Get the number of elements for the array
    printf("Enter number of elements:");

    // Dynamically allocate memory using malloc()
    ptr = (int*)malloc(n * sizeof(int));

    // Check if the memory has been successfully allocated
    if (ptr == NULL) {
        printf("Memory not allocated.\n");
    else {
        // Get the elements of the array
        for (i = 0; i < n; ++i) {
            ptr[i] = i + 1;

        // Print the elements of the array
        printf("The elements of the array are: ");
        for (i = 0; i < n; ++i) {
            printf("%d, ", ptr[i]);

    return 0;
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