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Login NowTo find the unit vector in the same direction as a vector, we divide it by its magnitude.

The magnitude of v is \(\sqrt{1^2 + (-2)^2 + 2^2 + 3^2}\) = \(\sqrt{18}\)

We will divide \(\vec{u}\) by magnitude of \(\vec{v}\). So,

\(\left ( \frac{1}{\sqrt{18}}, \frac{-2}{\sqrt{18}}, \frac{-2}{\sqrt{18}}, \frac{3}{\sqrt{18}} \right )\)

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