Find the solution of y” + 4y’ + 4 = 0.

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Solution:

y” + 4y’ + 4 = 0

The characteristics equation of given differential equation is

m2 + 4m + 4 = 0

Solving the above equation, We get

m = -2

Here, the roots are real and equal

The general solution are

y = (C1 + C2x)emx

y = (C1 + C2x)e-2x

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