Function is defined by f(x) = x + 2 if x

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Function is defined by f(x) = x + 2 if x < 0, compute f(-1), f(3) and sketch graph

Suresh Chand · Accepted Answer

Solution: Let f(x) = (left{begin{matrix} x + 2 enspace enspace if enspace x < 0 1 - x enspace enspace if enspace x > 0 end{matrix}right.) Then f(-1) = (-1) + 2 = 1 (We have used x + 2 since -1 < 0, and when x < 0 then function f(x) = x + 2) f(3) = 1 - 3 = -2 (We have used 1 - x since 3 > 0, and when x > 0 then function f(x) = 1 - x) For graph of f(x), given that f(x) = x + 2 for x < 0 i.e y = x + 2 Which is the linear equation, so is a straight line and it takes x -1 -2 y 1 0 This means y = x + 2 passes through (-1, 1) and (-2, 0). Also, given that f(x) = 1 - x for x > 0 i.e y = 1 - x Which is the linear equation, so is a straight line and it takes x 1 2 y 0 -1 This means y = x + 2 passes through (1, 0) and (2, -1). With these information, the graph of the equation is as:

A function is defined by f(x) = \(\left\{\begin{matrix}
x + 2 \enspace \enspace if \enspace x < 0\\
1 – x \enspace \enspace if \enspace x > 0
\end{matrix}\right.\), Concluate f(-1), f(3) and sketch graph.

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A function is defined by f(x) = \(\left\{\begin{matrix} x + 2 \enspace \enspace if \enspace x < 0\\ 1 – x \enspace \enspace if \enspace x > 0 \end{matrix}\right.\), Concluate f(-1), f(3) and sketch graph.

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A function is defined by f(x) = \(\left\{\begin{matrix}
x + 2 \enspace \enspace if \enspace x < 0\\
1 – x \enspace \enspace if \enspace x > 0
\end{matrix}\right.\), Concluate f(-1), f(3) and sketch graph.