roulette wheel with moment of inertia I = 0.5 kgm2 rotating initially at 2 rev/sec

Question

roulette wheel with moment of inertia I = 0.5 kgm2 rotating initially at 2 rev/sec

Suresh Chand · Accepted Answer

Solution:Given,Moment of Inertia (I) = 0.5 kgm2Torque (𝜏) = 0.4 NmFrequency (ω) = 2 rev/secTime to take it stop(t) = ?We know that𝜏 = I α(𝜏 = I frac{2pi f }{t})(0.4 = 0.5 frac{2 times pi times 2}{t})(frac{0.4}{0.5} = frac{4 times pi}{t})(t = frac{4 times pi times 0.5}{0.4})t = 15.7 secTherefore, 15.7 seconds is required to stop a roulette wheel.

A roulette wheel with moment of inertia I = 0.5 kgm² rotating initially at 2 rev/sec coasts to a stop from the constant friction torque of bearing. If the torque of the bearing. If the torque is 0.4 Nm, how long does it take to stop?

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A roulette wheel with moment of inertia I = 0.5 kgm2 rotating initially at 2 rev/sec coasts to a stop from the constant friction torque of bearing. If the torque of the bearing. If the torque is 0.4 Nm, how long does it take to stop?

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A roulette wheel with moment of inertia I = 0.5 kgm² rotating initially at 2 rev/sec coasts to a stop from the constant friction torque of bearing. If the torque of the bearing. If the torque is 0.4 Nm, how long does it take to stop?