Four spheres of diameter 2a amd mass M are placed with their centers on the corners of a square of side b. Then moment of inertia of the system about an axis avout one of the sides of the square is

$$Ma^2 + 2Mb^2$$

$$Ma^2 + 2Mb^2$$

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$$Ma^2$$

$$Ma^2$$

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$$Ma^2 + 4Mb^2$$

$$Ma^2 + 4Mb^2$$

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$$\frac{{8}}{{5}}Ma^2 + 2Mb^2$$

$$\frac{{8}}{{5}}Ma^2 + 2Mb^2$$

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